DisplayLayout.Open Method

Begin open layout
<ID("Open", (int)e.Open)> _ 
Public Function Open() As Boolean
This language is not supported or no code example is available.
[ID("Open", (int)e.Open)] 
public bool Open()
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Return Value

bool

Flag indicating success (true) or fail (false)

.NET Framework

Supported in: 4.6.2, 4.7

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Definition